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4(x^2+14x-176)=0
We multiply parentheses
4x^2+56x-704=0
a = 4; b = 56; c = -704;
Δ = b2-4ac
Δ = 562-4·4·(-704)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{14400}=120$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-120}{2*4}=\frac{-176}{8} =-22 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+120}{2*4}=\frac{64}{8} =8 $
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